JEE Chemistry · 225 questions · Page 3 of 23 · Click an option or "Show Solution" to reveal answer
Q21
Match the LIST-I with LIST-IILIST-I (Complex/ Species)LIST-II (Shape & magnetic moment)A. [Ni(CO)4]I. Tetrahedral, 2.8 BMB. [Ni(CN)4]2–II. Square planar, 0 BMC. [NiCl4]2–III. Tetrahedral, 0 BMD. [MnBr4]2–IV. Tetrahedral, 5.9 BMChoose the correct answer from the options given below:
AA-I, B-II, C-III, D-IV
BA-IV, B-I, C-III, D-II
CA-III, B-II, C-I, D-IV
DA-III, B-IV, C-II, D-I
Correct Answer
Option C
Solution
(A) [Ni(CO)4],Ni0:[Ar]3d84s2 Valence orbitals of Ni0 in pre-hybridisation state : Tetrahedral, Diamagnetic, μ=0 B.M.
(B) [Ni(CN)4]2−,Ni+2:[Ar]3d84s0 Valence orbitals of Ni+2 in pre-hybridisation state : Square planar, Diamagnetic, μ=0 B.M.
(C) [NiCl4]2−,Ni+2:[Ar]3d84s0 Valence orbitals of Ni+2 in ground state : Tetrahedral, paramagnetic, μ=8=2.8 B.M.
(D) [MnBr4]2−,Mn+2:[Ar]3d5 Valence orbitals of Mn+2 in ground state : Tetrahedral, paramagnetic, μ=35=5.9 B.M.
Q22
Which one of the following complexes shows optical isomerism? (en = ethylenediamine)
Acis[Co(en)2Cl2]Cl
Btrans[Co(en)2Cl2]Cl
C[Co(NH3)4Cl2]Cl
D[Co(NH3)3Cl3]
Correct Answer
Option A
Solution
Optical isomerism occurs when a molecule is non-superimposable with its mirror image hence the complex
cis−[Co(en)2Cl2]Cl
is optically active.
Q23
The coordination geometry around the manganese in decacarbonyldimanganese (0) is
ATrigonal bipyramidal
BSquare pyramidal
CSquare planar
DOctahedral
Correct Answer
Option D
Solution
Mn2(CO)10
Q24
Which one of the following complexes will consume more equivalents of aqueous solution of Ag(NO3)?
ANa3[CrCl6]
B[Cr(H2O)5Cl]Cl2
C[Cr(H2O)6]Cl3
DNa2[CrCl5(H2O)]
Correct Answer
Option C
Solution
[Cr(H2O)6]Cl3 has the highest primary valency among the given complexes, that is, three, therefore, it will consume three moles of AgNO3 and precipitate three moles of AgCl.
[Cr(H2O)6]Cl3 + 3AgNo3 → 3AgCl + [Cr(H2O)6](NO)3
Q25
Coordination compound have great importance in biological systems. In this context which of the following statements is incorrect?
AChlorophylls are green pigments in plants and contains calcium
BCarboxypeptidase – A is an enzyme and contains zinc
CCyanocobalamin is B12 and contains cobalt
DHaemoglobin is the red pigment of blood and contains iron
Correct Answer
Option A
Solution
The chlorophyll molecule plays an important role in photosynthesis, contain porphyrin ring and the metal
Mg
not
Ca.
Q26
Which of the following is an example of homoleptic complex?
A[Co(NH3)6]Cl3
B[Pt(NH3)2Cl2]
C[Co(NH3)4Cl2]
D[Co(NH3)5Cl]Cl2
Correct Answer
Option A
Solution
Homoleptic complexes are those compounds in which all the ligands bound to the central metal are identical.
Thus, these types of complexes have only one type of ligands.
In the complex [Co(NH3)6]Cl3 , central atom Co has ammonia ligands as all six.
Heteroleptic complexes are those compounds in which central transition metal has more than one type of ligands.
So, rest of the options are examples of heteroleptic complexes.
Q27
Which one the following has largest number of isomers? (R = alkyl group, en = ethylenediamine)
A[Ru(NH3)4Cl2]+
B[Co(en)2Cl2]+
C[Ir(PR3)2 H(CO)]2+
D[Co(NH3)5Cl]2+
Correct Answer
Option B
Solution
Isomers
Q28
The most stable ion is :
A[Fe(OH)3]3-
B[Fe(Cl)6]3-
C[Fe(CN)6]3-
D[Fe(H2O)6]3+
Correct Answer
Option C
Solution
The cyano and hydroxo complexes are far more stable than those formed by halide ion. This is due to the fact that
CN−
and
OH−
are strong lewis bases (nucleophiles). Further
[Fe(OH)5]3−
is not formed. hence most stable ion is
[Fe(CN)6]3−
Q29
CH3 - Mg - Br is an organometallic compound due to :
AMg - Br bond
BC - Mg bond
CC - Br bond
DC - H bond
Correct Answer
Option B
Solution
Compounds that contain at least one carbon metal bond are known as organometallic compounds. In
CH3
−Mg−Br
(Grignard's reagent) a bond is present between carbon and
Mg
(Metal) hence it is an organometallic compound.
Q30
Which of the following facts about the complex [Cr (NH3)6 ]Cl3 is wrong?
AThe complex is paramagnetic
BThe complex is an outer orbital complex
CThe complex gives white precipitate with silver nitrate solution
DThe complex involves d2sp3 hybridization and is octahedral in shape.
Correct Answer
Option B
Solution
[Cr(NH3)6]Cl3
is an inner orbital complex, because in this complex
d−
orbital used is of lower quantum number i.e.
(n−1).
It results from
d2
sp3
(inner orbital) hybridization.
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