p-Block Elements — Page 21 | JEE Chemistry

Q201

Diborane (B2H6) reacts with O2 and H2O independently, then products formed are :

A B2O3 and HBO2

B B2O3 and H3BO3

C HBO2 and H3BO3

D HBO2 and HBO3

Correct Answer

Option B

Solution

B2H6 + 3O2 $\to$ B2O3 + 3H2O B2H6 + 6H2O $\to$ 2H3BO3 + 6H2 $\uparrow$

Q202

Chlorine on reaction with hot and concentrated sodium hydroxide give :

A C

\ell

O

_3^ -

and C

\ell

O

_2^ -

B C

\ell

-

and C

\ell

O

-

C C

\ell

-

and C

\ell

O

_2^ -

D C

\ell

-

and C

\ell

O

_3^ -

Correct Answer

Option D

Solution

Hot and Concentrated.

Q203

The element that does NOT show catenation is :

A Ge

B Si

C Sn

D Pb

Correct Answer

Option D

Solution

All the four given element belongs to the carbon family. Pb will show last catenation.

Q204

Match with .tg .tg

List - I		List - II
(A)	N $_2$ (g) + 3H $_2$ (g) $\to$ 2NH $_3$ (g)	(I)	Cu
(B)	CO(g) + 3H $_2$ (g) $\to$ CH $_4$ (g) + H $_2$ O(g)	(II)	Cu/ZnO $-$ Cr $_2$ O $_3$
(C)	CO(g) + H $_2$ (g) $\to$ HCHO(g)	(III)	Fe $_x$ O $_y$ + K $_2$ O + Al $_2$ O $_3$
(D)	CO(g) + 2H $_2$ (g) $\to$ CH $_3$ OH(g)	(IV)	Ni

A

(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})

B

(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{III})

C

(\mathrm{~A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})

D

(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})

Correct Answer

Option C

Solution

Here, we have to match the reactions with their correct catalyst : (A)

\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \stackrel{\mathrm{Fe}_{\mathrm{x}} \mathrm{O}_{\mathrm{y}}+\mathrm{K}_{2} \mathrm{O}+\mathrm{Al}_{2} \mathrm{O}_{3}}{\longrightarrow} 2 \mathrm{NH}_{3}(\mathrm{~g})

(B)

\mathrm{CO}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{~g}) \stackrel{\mathrm{Ni}}{\longrightarrow} \mathrm{CH}_{4}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g})

(C)

\mathrm{CO}(\mathrm{g})+\mathrm{H}_{2}(\mathrm{~g}) \stackrel{\mathrm{Cu}}{\longrightarrow} \mathrm{HCHO}(\mathrm{g})

(D)

\mathrm{CO}(\mathrm{g})+2 \mathrm{H}_{2} (g) \stackrel{\mathrm{Cu} / \mathrm{ZnO}-\mathrm{Cr}_{2} \mathrm{O}_{3}}{\longrightarrow} \mathrm{CH}_{3}-\mathrm{OH}(\mathrm{g})

$\therefore$ Option (C) is correct option.

Q205

Match with : .tg .tg

List - I		List - II
(A)	Sulphate	(I)	Pesticide
(B)	Fluoride	(II)	Bending of bones
(C)	Nicotine	(III)	Laxative effect
(D)	Sodium arsinite	(IV)	Herbicide

A A-II, B-III, C-IV, D-I

B A-IV, B-III, C-II, D-I

C A-III, B-II, C-I, D-IV

D A-III, B-II, C-IV, D-I

Correct Answer

Option C

Solution

Sodium arsinite - Herbicide Nicotine - Pesticide Sulphate - Laxative effect Fluoride - Bending of bones

Q206

Match with . .tg .tg (Processes / Reactions) (Catalyst)

List - I		List - II
(A)	2SO $_2$ (g) + O $_2$ (g) $\to$ 2SO $_3$ (g)	(I)	Fe(s)
(B)	4NH $_3$ (g) + 5O $_2$ (g) $\to$ 4NO(g) + 6H $_2$ O(g)	(II)	Pt(s) $-$ Rh(s)
(C)	N $_2$ (g) + 3H $_2$ (g) $\to$ 2NH $_3$ (g)	(III)	V $_2$ O $_5$
(D)	Vegetable oil(l) + H $_2$ $\to$ Vegetable ghee(s)	(IV)	Ni(s)

A

(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{IV})

B

(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})

C

(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})

D

(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{I})

Correct Answer

Option B

Solution

(A)

2 \mathrm{SO}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \stackrel{\mathrm{V}_{2} \mathrm{O}_{5}}{\longrightarrow} 2 \mathrm{SO}_{3}

(B)

4 \mathrm{NH}_{3}(\mathrm{g})+5 \mathrm{O}_{2}(\mathrm{g}) \stackrel{\mathrm{Pt}(\mathrm{s})-\mathrm{Rh}(\mathrm{s})}{\longrightarrow} 4 \mathrm{NO}(\mathrm{g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})

(C)

\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \stackrel{\mathrm{Fe}(\mathrm{s})}{\longrightarrow} 2 \mathrm{NH}_{3}(\mathrm{g})

(D) Vegetable oil(I)

+\mathrm{H}_{2} \stackrel{\mathrm{Ni(s})}{\longrightarrow}

Vegetable ghee(s)

Q207

Match List I with List II .tg .tg LIST I Name of reaction LIST II Reagent used A. Hell-Volhard-Zelinsky reaction I.

NaOH + {I_2}

B. Iodoform reaction II. (i)

Cr{O_2}C{l_2},C{S_2}

(ii)

{H_2}O

C. Etard reaction III. (i)

B{r_2}

/ red phosphorus (ii)

H_2O

D. Gatterman-Koch reaction IV.

CO,HCl,

, anhyd.

AlC{l_3}

Choose the correct answer from the options given below:

A A-III, B-I, C-IV, D-II

B A-III, B-I, C-II, D-IV

C A-I, B-II, C-III, D-IV

D A-III, B-II, C-I, D-IV

Correct Answer

Option B

Solution

Hell-Volhard-Zelinsky reaction involves halogenation and is carried out using halogens like bromine along with red phosphorus and water.

So, A matches with III.

Iodoform reaction involves the reaction of iodine and sodium hydroxide.

So, B matches with I.

Etard reaction involves the oxidation of aromatic aldehydes and is carried out using chromyl chloride (

\mathrm{CrO_2Cl_2}

) and carbon disulfide (

\mathrm{CS_2}

), followed by water.

So, C matches with II.

Gatterman-Koch reaction involves the formation of aromatic aldehydes using carbon monoxide, hydrochloric acid, and anhydrous aluminum chloride.

So, D matches with IV.

So, the correct option is : Option B A-III, B-I, C-II, D-IV

Q208

Correct statements among a to d regarding silicones are : (a) They are polymers with hydrophobic character. (b) They are biocompatible. (c) In general, they have high thermal stability and low dielectric strength. (d) Usually, they are resistant to oxidation and used as greases.

A (a), (b), (c) and (d)

B (a), (b) and (c) only

C (a) and (b) only

D (a), (b) and (d) only

Correct Answer

Option D

Solution

(a) and (b) are properties of silicone. (d) is the uses of silicone.

Q209

XeF6 on partial hydrolysis with water produces a compound ‘X’. The same compound ‘X’ is formed when XeF6 reacts with silica. The compound ‘X’ is :

A XeF2

B XeF4

C XeOF4

D XeO3

Correct Answer

Option C

Solution

XeF6 on hydrolysis with water can produces 3 compounds XeOF4, XeO2F2 and XeO3.

Here XeOF4 and XeO2F2 are produced on partial hydrolysis and XeO3 is produced on complete hydrolysis.

XeF6 + H2O

\overset{{Partial}}\longrightarrow

XeOF4 + 2HF XeF6 + 2H2O

\overset{{Partial}}\longrightarrow

XeO2F2 + 4HF XeF6 + 3H2O

\overset{{Complete}}\longrightarrow

XeO3 + 6HF So, the compound X can be XeOF4 or XeO2F2 Reaction with silica (SiO2) of XeF6 : When ration of XeF6 and SiO2 is 2 : 1 then produce XeOF4.

2XeF6 + SiO2 $\to$ 2XeF4 + SiF4 When ratio of XeF6 and SiO2 is 1 : 1 , then produce XeO2F2.

XeF6 + SiO2 $\to$ XeO2F2 + SiF4 So, the compound X can be XeOF4 or XeO2F2.

Here in option only XeOF4 is given so this will be right answer.

Q210

Aqua regia is used for dissolving noble metals (Au, Pt, etc.). The gas evolved in this process is :

A N2O3

B N2

C N2O5

D NO

Correct Answer

Option D

Solution

Au + 4H+ + NO3- + 4Cl- $\to$ AuCl4- + NO + 2H2O 3Pt + 16H+ + 4NO3- + 18Cl- $\to$ 3PtCl62- + 4NO + 8H2O