Metamerism arises due to different alkyl chains on either side of the functional group in the molecule pair of molecules and are metamers of each other.
Phthalein Dye test: Phenol on heating with phthalic anhydride in presence of concentrated sulphuric acid forms a colourless condensation compound called phenolphthalein.
On further reaction with NaOH it gives pink colour.
So phenolic group is correct answer.
Tertiary alcohols react instantaneously with Lucas reagent and gives immediate turbidity.
In case of tertiary alcohols, they form halides easily with Lucas reagent (conc.
and
)
Let's analyze the given reactions and determine the products
and
. Reaction with PCl 3 : When an alcohol (
) reacts with phosphorus trichloride (
), the hydroxyl group (
) of the alcohol is replaced by a chloro group (
), resulting in the formation of an alkyl chloride (
). Additionally, the reaction produces phosphorous acid as a byproduct. This can be represented as:
Here,
is
(phosphorous acid). Reaction with PCl 5 : When an alcohol reacts with phosphorus pentachloride (
), it also replaces the hydroxyl group with a chloro group.
The reaction differs slightly in the byproducts; phosphorus oxychloride (
) and hydrogen chloride (
) are produced:
Here,
is
(phosphorus oxychloride). Thus, in the reactions provided:
Matching these findings against the provided options, we see that Option D correctly identifies
as
and
as
: Option D:
and
This is the correct answer.
At STP condition substitution at sp 2 carbon atom is not feasible.
In case of phenyl methyl ether, methyl phenyl oxonium ion is formed by protonation of ether.
The O—CH 3 bond is weaker than O—C 6 H 5 bond as O—C 6 H 5 has partial double bond character.
Therefore, the attack by I– ion breaks O—CH 3 bond to form CH 3 I.
The treatment of sodium alkoxide with a suitable alkyl halide to form an ether is called as Williamson ether synthesis reaction.
Lucas reagent [HCl + ZnCl 2 ] can be used for 1 o / 2 o / 3 o -alcohol but if ZnCl 2 is absent then only 3 o alcohol can be used because it is most reactive due to 3 o carbocation.
This is Reimer–Tiemann reaction.
