Hydrogen

NEET Chemistry · 90 questions · Page 2 of 9 · Click an option or "Show Solution" to reveal answer

Q11
The synonym for water gas when used in the production of methanol is :
A fuel gas
B laughing gas
C syn gas
D natural gas
Correct Answer
Option C
Solution

H2O(g) + C \to CO + H2 The gaseous mixture CO + H2 which is produced when steam is passed over red hot coke and this mixture called water gas or synthesis gas or syn gas.

Q12
The correct statements among (a) to (d) are : (a) saline hydrides produce H2 gas when reacted with H2O. (b) reaction of LiAlH4 with BF3 leads to B2H6. (c) PH3 and CH4 are electron - rich and electron - precise hydrides, respectively. (d) HF and CH4 are called as molecular
A (a), (b), (c) and (d)
B (a), (c) and (d) only
C (c) and (d) only
D (a), (b) and (c) only
Correct Answer
Option A
Solution

(a) NaH + H2O \to NaOH + H2 (b) 3LiAlH4 + 4BF3 \to 2B2H6 + 3LiF + 3AlF3 (c) PH3 is electron rich due to one lone pair while CH4 is electron precise hydride. (d) HF and CH4 are molecular hydrides.

Q13
The strength of 11.2 volume solution of H2O2 is : [Given that molar mass of H = 1 g mol–1 and O = 16 g mol–1]
A 3.4%
B 34%
C 13.6%
D 1.7%
Correct Answer
Option A
Solution

Strength means

WeightVolume{{Weight} \over {Volume}}

%. Molarity of H2O2 =

volumestrength11.2{{volume\,strength} \over {11.2}}

=

11.211.2{{11.2} \over {11.2}}

= 1 M = 34 gm/lit In 1000 ml solution 34 gm H2O2 present \therefore In 100 ml solution 3.4 gm H2O2 present.

Q14
Which of the following equation depicts the oxidizing nature of H2O2?
A Cl2+H2O22HCl+O2C{l_2} + {H_2}{O_2} \to 2HCl + {O_2}
B KIO4+H2O2KIO3+H2O+O2KI{O_4} + {H_2}{O_2} \to KI{O_3} + {H_2}O + {O_2}
C 2I+H2O2+2H+I2+2H2O2{I^ - } + {H_2}{O_2} + 2{H^ + } \to {I_2} + 2{H_2}O
D I2+H2O2+2OH2I+2H2O+O2{I_2} + {H_2}{O_2} + 2O{H^ - } \to 2{I^ - } + 2{H_2}O + {O_2}
Correct Answer
Option C
Solution
2I+H2O2+2H+I2+2H2O2{I^ - } + {H_2}{O_2} + 2{H^ + } \to {I_2} + 2{H_2}O

Oxygen reduces from –1 to –2.

So, its reduction will takes place.

Hence it will behave as oxidising agent or it shows oxidising nature.

While in other option it change from (–1) to 0.

Q15
Statements about heavy water are given below : A. Heavy water is used in exchange reactions for the study of reaction mechanisms. B. Heavy water is prepared by exhaustive electrolysis of water. (C) Heavy water has higher boiling point than ordinary water. (D) Viscosity of H2O is greater than D2O. Choose the most appropriate answer from the options given below :
A A, B, and C only
B A and C only
C A and D only
D A and B only
Correct Answer
Option A
Solution

Viscosity of D2O is greater than H2O. B.P. of D2O is greater than H2O.

Q16
Which of the following could act as a propellant for rockets?
A Liquid oxygen + liquid argon
B Liquid hydrogen + liquid oxygen
C Liquid nitrogen + liquid oxygen
D Liquid hydrogen + liquid nitrogen
Correct Answer
Option B
Solution

Liquid hydrogen and liquid oxygen are used as excellent fuel for rockets.

H2(){H_2}\left( \ell \right)

has low mass and high enthalpy of combustion whereas oxygen is a strong supporter of combustion.

Q17
In context with the industrial preparation of hydrogen from water gas (CO + H2), which of the following is the correct statement?
A CO and H2 are fractionally separated using differences in their densities
B CO is removed by absorption in aqueous Cu2Cl2 solution
C H2 is removed through occlusion with Pd
D CO is oxidised to CO2 with steam in the presence of a catalyst followed by absorption of CO2 in alkali
Correct Answer
Option D
Solution

On the industrial scale hydrogen is prepared from water gas according to following reaction sequence

CO+H2watergas+H2O(steam)catalystCO2+2H2\underbrace {CO + {H_2}}_{water\,\,\,gas} + \underbrace {{H_2}O}_{\left( {steam} \right)}\,\,\overset{{catalyst}}\longrightarrow C{O_2} + 2{H_2}
(alkali)2NaOHNa2CO3+H2O\,\,\,\,\,\,\,\,\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{\left( {alkali} \right)}^{2NaOH}} N{a_2}C{O_3} + {H_2}O

From the above it is clear that

COCO

is first oxidised to

CO2C{O_2}

which is then ansorbed in

NaOH.NaOH.
Q18
Very pure hydrogen (99.9%) can be made by which of the following processes?
A Reaction of methane with steam
B Mixing natural hydrocarbons of high molecular weight
C Electrolysis of water
D Reaction of salt like hydrides with water
Correct Answer
Option D
Solution

Very pure hydrogen (99.9%) can be prepared by the action of water on any hydrides i.e, sodium hydride(NaH), Calcium Hydride(CaH2) etc.

NaH+H2ONaOH+H2NaH + {H_2}O \to NaOH + {H_2}

(very pure Hydrogen) By electrolysis of water we get 99.5% pure hydrogen. 2H2O

Electrolysis\overset{{Electrolysis}}\longrightarrow

2H2 + O2 Note : By electrolysis of water we can't get 99.9% pure hydrogen we only get around 99.5% pure hydrogen.

That is why option (C) is wrong.

Q19
The metal that gives hydrogen gas upon treatment with both acid as well as base is :
A mercury
B zinc
C iron
D magnesium
Correct Answer
Option B
Solution

Zn + 2HCl \to ZnCl2 + H2 Zn + NaOH \to Na2ZnO2 + H2 Here zinc(Zn) is amphoteric metal, that is why it reacts with both acid and base.

Q20
100 mL of a water sample contains 0.81 g of calcium bicrabonate and 0.73 g of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalents of CaCO3 is : (Molar mass of calcium bicarbonate is 162 g mol–1 and magnesium bicarbonate is 146 g mol–1)
A 1,000 ppm
B 100 ppm
C 10,000 ppm
D 5,000 ppm
Correct Answer
Option C
Solution

Here hardness of water is expressed in terms of CaCO3.

\therefore Equivalent of CaCO3 = Equivalent of Ca(HCO3)2 + Equivalent of Mg(HCO3)2 \Rightarrow 2 ×\times

W100{W \over {100}}

=

0.81162×2+0.73146×2{{0.81} \over {162}} \times 2 + {{0.73} \over {146}} \times 2

\Rightarrow W = 1 gm Volume of water = 100 mL \therefore Mass of water = 100 g \therefore Hardness =

1.0100×106{{1.0} \over {100}} \times {10^6}

= 10000 ppm

Ready for a full NEET mock test? Timed · full syllabus · instant results
Take a Mock Test →