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Organic Compounds Containing Nitrogen

NEET Chemistry · 61 questions · Page 2 of 7 · Click an option or "Show Solution" to reveal answer

Q11
The number of structural isomers possible from the molecular formula C 3 H 9 N is
A 5
B 2
C 3
D 4
Correct Answer
Option D
Solution

Total 4 structural isomers are possible.

Q12
Method by which aniline cannot be prepared is
A degradation of benzamide with bromine in alkaline solution
B reduction of nitrobenzene with H 2 /Pd in ethanol
C potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous NaOH solution
D hydrolysis of phenylisocyanide with acidic solution.
Correct Answer
Option C
Solution

Because arylhalides do not undergo nucleophilic substitution reaction with potassium phthalimide easily.

Q13
The following reaction is known by the name
A Perkin's reaction
B Acetylation reaction
C Schotten-Baumann reaction
D Friedel-Craft's reaction
Correct Answer
Option C
Solution

Schotten-Bauman reaction is a method to synthesize amides from amines and acid chlorides.

Q14
Which of the following will be most stable diazonium salt R N 2 + X −- ?
A CH 3 N 2 + X −-
B C 6 H 5 N 2 + X −-
C CH 3 CH 2 N 2 + X −-
D C 6 H 5 CH 2 N 2 + X −-
Correct Answer
Option B
Solution

Diazonium salt containing aryl group directly linked to the nitrogen atom is most stable due to resonance stabilization.

Q15
Some reactions of amines are given. Which one is not correct?
A
B CH 3 CH 2 NH 2 + HNO 2 → \to CH 3 CH 2 OH + N 2
C CH 3 NH 2 + C 6 H 5 SO 2 Cl → \to CH 3 NHSO 2 C 6 H 5
D (CH 3 ) 2 NH + NaNO 2 + HCl → \to (CH 3 ) 2 N −- N == O
Correct Answer
Option A
Solution

Secondary amine react with nitrous acid to give N-Nitrosoamines.

Q16
On hydrolysis of a ''compound'', two compounds are obtained. One of which one treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollens reagent and Fehling's solution. The ''compound'' is
A CH 3 CH 2 CH 2 NC
B CH 3 CH 2 CH 2 CN
C CH 3 CH 2 CH 2 ON == O
D CH 3 CH 2 CH 2 CON(CH 3 ) 2
Correct Answer
Option A
Solution

Hydrolysis of propyl isocyanide (CH 3 CH 2 CH 2 NC) gives CH 3 CH 2 CH 2 NH 2 + HCOOH.

On treatment with NaNO 2 and HCl I(CH 3 CH 2 CH 2 NH 2 ) gives CH 3 CH 2 CH 2 OH which does not give iodoform test.

II (HCOOH) reduces Tollen’s reagent and Fehling’s solution.

Q17
In the reaction A is
A H 3 PO 2 and H 2 O
B H + /H 2 O
C HgSO 4 /H 2 SO 4
D Cu 2 Cl 2
Correct Answer
Option A
Solution

H 3 PO 2 and H 2 O works as a reducing agent.

Q18
An organic compound (C 3 H 9 N) (A), when treated with nitrous acid, gave an alcohol and N 2 gas was evolved. (A) on warming with CHCl 3 and caustic potash gave (C) which on reduction gave isopropylmethylamine. Predict the structure of (A)
A
B CH 3 CH 2 −- NH −- CH 3
C
D CH 3 CH 2 CH 2 −- NH 2
Correct Answer
Option A
Solution

As A gives alcohol on treatment with nitrous acid thus it should be primary amine.

C 3 H 9 N has two possible structure with –NH 2 group.

As it gives isopropylmethylamine thus it should be isopropyl amine not n-propyl amine.

Q19
Acetamide is treated with the following reagents separately. Which one of these would yield methyl amine?
A NaOH/Br 2
B Sodalime
C Hot conc.H 2 SO 4
D PCl 5
Correct Answer
Option A
Solution

Among the given reagents only NaOH/ Br 2 converts -CONH 2 group to -NH 2 group.

This is known as Hofmann bromamide reaction.

CH 3 -CONH 2 + NaOH +Br 2 →\to CH 3 NH 2 + NaBr + Na 2 CO 3 + H 2 O

Q20
Which of the following statements about primary amines is false?
A Alkyl amines are stronger bases than aryl amines.
B Alkyl amines react with nitrous acid to produce alcohols.
C Aryl amines react with nitrous acid to produce phenols.
D Alkyl amines are stronger bases than ammonia.
Correct Answer
Option C
Solution

Aryl amines react with nitrous acid to form diazonium salt.

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