Q151
The dimensions of Planck's constant equals to that of
Correct Answer
Option C
Solution
Plank constant (h) =
=
= [ML 2 T -1 ] Angular momentum (L) = I = [ML 2 ][T -1 ] = [ML 2 T -1 ]
Plank constant (h) =
=
= [ML 2 T -1 ] Angular momentum (L) = I = [ML 2 ][T -1 ] = [ML 2 T -1 ]
Dimension of force = [MLT -2 ] Dimension of impulse = [MLT -1 ] So both of them have different dimensions.