Ce4+
Ce3+ E° = +1.74 V Positive SRP and higher SRP means greater oxidising power.
So, Ce4+ wants to reduce to Ce3+.
Indicates Ce4+ is less stable than Ce3+.
Ce4+
Ce3+ E° = +1.74 V Positive SRP and higher SRP means greater oxidising power.
So, Ce4+ wants to reduce to Ce3+.
Indicates Ce4+ is less stable than Ce3+.
The third ionisation energy of Mn is too high due to stable half filled 3d-orbital.
Hence, it cannot further get oxidised to liberate hydrogen.
When a solution of potassium chromate is treated with an excess of dilute nitric acid. Potassium dichromate and
are formed.
Hence
and
are formed.
Fe (Z = 26) e- = 26 Fe2+ (Z = 26) e- = 24 Electronic configuration: Fe (Z = 26) 1s2 2s2 2p6 3s2 3p6 3d6 4s2 Fe2+ (Z = 26) 1s2 2s2 2p6 3s2 3p6 3d6 4s0 as 4s is the outermost shell of Fe that's why e- will always removed first from 4s, so retained e- in d-shell is 6
The number of unpaired electrons in
Water is weak ligand hence no pairing will take place spin magnetic moment
The main reason of lanthanide contraction is, poor shielding of 4f electrons on the outer most shell electrons.
As f orbital is defused nature so shielding of 4f electron is imperfect that is why nucleus can attract outer most shell electron easily and the size of atom decreases.
In lanthanides, there is poorer shielding of
electrons by
electrons resulting in greater attraction of the nucleus over
electrons and reduction of the atomic radii.
orbital is nearer to nucleus as compared to
orbital therefore, shielding of
is more than
Atomic radius of Ag and Au is nearly same due to lanthanide contraction.
In periodic table in group 1, 2, 3 from top to bottom radius increases but from group 4 to 12 size increases for 3d to 4d series elements but size of 4d and 5d series elements are approximately same.
is easily hydrolysed than
due to more positive charge.
In equation (i)
and in equation (ii)
on decomposing will form oxide instead of
The correct sequence of reactions is