Heat and Thermodynamics

JEE Physics · 315 questions · Page 4 of 32 · Click an option or "Show Solution" to reveal answer

Q31
1 mole of a gas with γ=7/5\gamma = 7/5 is mixed with 11 mole of a gas with γ=5/3,\gamma = 5/3, then the value of γ\gamma for the resulting mixture is
A 7/57/5
B 2/52/5
C 3/23/2
D 12/712/7
Correct Answer
Option C
Solution

If

n1{n_1}

moles of adiabatic exponent

γ1{\gamma _1}

is mixed with

n2{n_2}

moles of adiabatic exponent

γ2{\gamma _2}

then the adiabatic component of the resulting mixture is given by

n1+n2γ1=n1γ11+n2γ21{{{n_1} + {n_2}} \over {\gamma - 1}} = {{{n_1}} \over {{\gamma _1} - 1}} + {{{n_2}} \over {{\gamma _2} - 1}}
1+1γ1=1751+1531{{1 + 1} \over {\gamma - 1}} = {1 \over {{7 \over 5} - 1}} + {1 \over {{5 \over 3} - 1}}

\therefore

2γ1=52+32=4{2 \over {\gamma - 1}} = {5 \over 2} + {3 \over 2} = 4

\therefore

2=4γ4γ=64=322 = 4\gamma - 4 \Rightarrow \gamma = {6 \over 4} = {3 \over 2}
Q32
Two spheres of the same material have radii 11 mm and 44 mm and temperatures 40004000 KK and 20002000 KK respectively. The ratio of the energy radiated per second by the first sphere to that by the second is
A 1:11:1
B 16:116:1
C 4:14:1
D 1:91:9
Correct Answer
Option A
Solution

The energy radiated per second is given by

E=eσT4AE = e\sigma {T^4}A

For same material

ee

is same. σ\sigma is stefan's constant \therefore

E1E2=T14A1T24A2=T144πr12T244πr22{{{E_1}} \over {{E_2}}} = {{T_1^4{A_1}} \over {T_2^4{A_2}}} = {{T_1^44\pi r_1^2} \over {T_2^44\pi r_2^2}}
=(4000)4×12(2000)4×42=11= {{{{\left( {4000} \right)}^4} \times {1^2}} \over {{{\left( {2000} \right)}^4} \times {4^2}}} = {1 \over 1}
Q33
During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature. The ratio Cp/CV{C_p}/{C_V} for the gas is
A 43{4 \over 3}
B 22
C 53{5 \over 3}
D 32{3 \over 2}
Correct Answer
Option D
Solution
PT3PT3=P \propto {T^3} \Rightarrow P{T^{ - 3}} =

constant ....

(i)(i)

But for an adiabatic process, the pressure temperature relationship is given by

P1γTγ={P^{1 - \gamma }}\,\,{T^\gamma } =

constant

PTγ1γ=\Rightarrow P{T^{{\gamma \over {1 - \gamma }}}} =

constant. ....

(ii)(ii)

From

(i)(i)

and

(ii)(ii)
γ1γ=3γ=3+3γγ=32{\gamma \over {1 - \gamma }} = - 3 \Rightarrow \gamma = - 3 + 3\gamma \Rightarrow \gamma = {3 \over 2}
Q34
The earth radiates in the infra-red region of the spectrum. The spectrum is correctly given by
A Rayleigh Jeans law
B Planck's law of radiation
C Stefan's law of radiation
D Wien's law
Correct Answer
Option D
Solution

Wein's law correctly explanations the spectrum

Q35
A carnot engine takes 3×1063 \times {10^6} cal. of heat from a reservoir at 627C,{627^ \circ }C, and gives it to a sink at 27C{27^ \circ }C. The work done by the engine is
A 4.2×106J4.2 \times {10^6}J
B 8.4×106J8.4 \times {10^6}J
C 16.8×106J16.8 \times {10^6}J
D zero
Correct Answer
Option B
Solution
η=1T2T1\eta = 1 - {{{T_2}} \over {{T_1}}}
=1(273+27)(273+627)= 1 - {{\left( {273 + 27} \right)} \over {\left( {273 + 627} \right)}}
=1300900= 1 - {{300} \over {900}}
=113=23= 1 - {1 \over 3} = {2 \over 3}

But

η=WQ\eta = {W \over Q}

\therefore

WQ=23W{W \over Q} = {2 \over 3} \Rightarrow W
=23×Q= {2 \over 3} \times Q
=23×3×106= {2 \over 3} \times 3 \times {10^6}
=2×106cal= 2 \times {10^6}cal
=2×106×4.2J= 2 \times {10^6} \times 4.2\,J
=8.4×106J= 8.4 \times {10^6}J
Q36
Which of the following parameters does not characterize the thermodynamic state of mattter?
A Temperature
B Pressure
C Work
D Volume
Correct Answer
Option C
Solution

Work is a path function. The remaining three parameters are state function.

Q37
The rms speeds of the molecules of Hydrogen, Oxygen and Carbon dioxide at the same temperature are VH, VO and VC respectively then :
A VH > VO > VC
B VC > VO > VH
C VH = VO > VC
D VH = VO = VC
Correct Answer
Option A
Solution
VRMS=3RTMW{V_{RMS}} = \sqrt {{{3RT} \over {{M_W}}}}

At the same temperature

VRMS1MW{V_{RMS}} \propto {1 \over {\sqrt {{M_W}} }}

\Rightarrow VH > VO > VC Option (a)

Q38
Heat given to a body which raises its temperature by 1C{1^ \circ }C is
A water equivalent
B thermal capacity
C specific heat
D temperature gradient
Correct Answer
Option B
Solution

Heat required for raising the temperature of the whole body by

1C{1^ \circ }C

is called the thermal capacity of the body.

Q39
Which of the following is more close to a black body?
A black board paint
B green leaves
C black holes
D red roses
Correct Answer
Option A
Solution

Black board paint is quite approximately equal to black bodies.

Q40
If mass-energy equivalence is taken into account, when water is cooled to form ice, the mass of water should
A increase
B remain unchanged
C decrease
D first increase then decrease
Correct Answer
Option C
Solution

When water is cooled to form ice, energy is released from water in the form of heat.

As energy is equivalent to mass therefore when water is cooled to ice, its mass decreases.

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