Q71
The energy required to break one bond in DNA is 10 -20 J. This value in eV is nearly :
Correct Answer
Option B
Solution
Least count = Pitch/No of divisions. 0.01 = Pitch/50. Pitch = 0.5 mm
Answer is 7.6 due to significant figures (2 sig figs from side measurement).
LC = 1 MSD - 1 VSD = 1mm - (16/20)mm = 0.2mm = 0.02 cm
Time s. Distance
2 significant figures from side: 7.6
LC = 1 - 16/20 = 0.2 mm = 0.02 cm
3(1)+2(3)+2+0.5(4)=13%
, speed of light =
Dimensional analysis gives p=r=1/2, q=-3/2. L =