Coordination Compounds Questions — NEET Chemistry

Q1

Which one of the following is an ambidentate ligand?

A Ethane-1,2-diamine

B Ethylenediaminetetraacetate ion

C Thiocyanate

D Oxalate

Correct Answer

Option C

Solution

An ambidentate ligand is a ligand which has two different donor atoms and either of the two ligates in complex.

(1) Ethane-1,2-diamine → didentate (2) Ethylenediamine tetraacetate ion → hexadentate (3) Thiocyanate $\left(\mathrm{SCN}^{-}\right) \rightarrow$ Ambidentate ligand.

(4) Oxalate → didentate

Q2

Ethylene diaminetetraacetate ion is a/an:

A hexadentate ligand

B ambidentate ligand

C monodentate ligand

D bidentate ligand

Correct Answer

Option A

Solution

Ethylene diaminetetraacetate It is hexadentate as it can bind through two nitrogen and four oxygen atoms to a central metal ion.

Q3

Which of the following is not an ambidentate ligand?

A

\mathrm{C}_2 \mathrm{O}_4^{2-}

B SCN

^-

C NO

_2^-

D CN

^-

Correct Answer

Option A

Solution

Ambidentate ligands are those ligands which have two different donor atoms and either of two donor atom is attached to the metal during complex formation.

Q4

Select the element (M) whose trihalides cannot be hydrolysed to produce an ion of the form [M(H

_2

O

_6

]

^{3+}

A Ga

B In

C Al

D B

Correct Answer

Option D

Solution

Maximum covalency of boron is four.

Q5

Which of the following forms a set of complex and a double salt, respectively?

A

\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}

and

\mathrm{CuCl}_2, 4 \mathrm{NH}_3

B

\mathrm{PtCl}_2 \cdot 2 \mathrm{NH}_3

and

\mathrm{PtCl}_4 \cdot 2 \mathrm{HCl}

C

\mathrm{K}_2 \mathrm{PtCl}_2 \cdot 2 \mathrm{NH}_3

and

\mathrm{KAl}\left(\mathrm{SO}_4\right)_2 \cdot 12 \mathrm{H}_2 \mathrm{O}

D

\mathrm{NiCl}_2 \cdot 6 \mathrm{H}_2 \mathrm{O}

and

\mathrm{NiCl}_2\left(\mathrm{H}_2 \mathrm{O}\right)_4

Correct Answer

Option C

Solution

Complex salt is

\mathrm{K}_2\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}_2\right]

Double salt is

\mathrm{KAl}\left(\mathrm{SO}_4\right)_2 \cdot 12 \mathrm{H}_2 \mathrm{O}

(potash alum)

Q6

Type of isomerism exhibited by compounds

\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6 \mathrm{Cl}_3,\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{Cl}_2 \mathrm{Cl}_2 \cdot \mathrm{H}_2 \mathrm{O}\right.\right.,\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl} .2 \mathrm{H}_2 \mathrm{O}

and the value of coordination number

(\mathrm{CN})

of central metal ion in all these compounds, respectively is :

A Geometrical isomerism, CN = 2

B Optical isomerism, CN = 4

C Ionisation isomerism, CN = 4

D Solvate isomerism, CN = 6

Correct Answer

Option D

Solution

Given complex compounds exhibit solvate isomerism having co-ordination number = 6.

Q7

Homoleptic complex from the following complexes is :

A Diamminechloridonitrito-N-platinum (II)

B Pentaamminecarbonatocobalt (III) chloride

C Triamminetriaquachromium (III) chloride

D Potassium trioxalatoaluminate (III)

Correct Answer

Option D

Solution

(1)

\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}\left(\mathrm{NO}_{2}\right)\right]

(2)

\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5}\left(\mathrm{CO}_{3}\right)\right] \mathrm{Cl}

(3)

\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{3}\left(\mathrm{H}_{2} \mathrm{O}\right)_{3}\right] \mathrm{Cl}_{3}

(4)

\mathrm{K}_{3}\left[\mathrm{Al}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]

Option 4 contain all ligands are of same type i.e. why complex will be homoleptic.

Q8

Which complex compound is most stable?

A

\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3}\left(\mathrm{NO}_{3}\right)_{3}\right]

B

\left[\mathrm{CoCl}_{2}(\mathrm{en})_{2}\right] \mathrm{NO}_{3}

C

\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]_{2}\left(\mathrm{SO}_{4}\right)_{3}

D

\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{Br}\right]\left(\mathrm{NO}_{3}\right)_{2}

Correct Answer

Option B

Solution

due to Chelation effect of (en).

Q9

The IUPAC name of the complex - [Ag(H 2 O) 2 ][Ag(CN) 2 ] is:

A dicyanidosilver(II) diaquaargentate (II)

B diaquasilver(II) dicyanidoargentate(II)

C dicyanidosilver(I) diaquaargentate(I)

D diaquasilver(I) dicyanidoargentate(I)

Correct Answer

Option D

Solution

[Ag(H 2 O) 2 ][Ag(CN) 2 ] IUPAC name : diaquasilver(I) dicyanidoargentate(I)

Q10

The order of energy absorbed which is responsible for the color of complexes (A) [Ni(H 2 O) 2 (en) 2 ] 2+ (B) [Ni(H 2 O) 4 (en) ] 2+ and (C) [Ni(en) 3 ] 2+ is

A (A) > (B) > (C)

B (C) > (B) > (A)

C (C) > (A) > (B)

D (B) > (A) > (C)

Correct Answer

Option C

Solution

Stronger the field strength of ligand, higher will be the energy absorbed by the complex. $\Rightarrow$ 'en' has a stronger field strength than 'H 2 O' according to spectrochemical series $\therefore$ Correct order of energy absorbed will be : [Ni(en) 3 ] 2+ > [Ni(H 2 O) 2 (en) 2 ] 2+ > [Ni(H 2 O) 4 (en)] 2+ i.e.

(C) > (A) > (B)