Thus, the number of unpaired electrons = 4.
Coordination Compounds
-bonded organometallic compound includes organometallic compounds of alkenes, alkynes and some other carbon containing compounds having electrons in their p orbitals.
Atoms, ions or molecules containing unpaired electrons are paramagnetic.
In [Cr(NH 3 ) 6 ] 3+ Cr +3 = [Ar]3d 3 4s 0 NH 3 is weak field ligand so pairing of d-electrons take place odes not happen.
Here, Number of unpaired electrons = 3 So it is paramagnetic.
In other cases pairing of d-electrons take place in presence of strong field ligands such as CO or CN – .
Copper sulphate react with KCN to give white ppt of CuCN and cyanogen gas.
The insoluble copper cyanide dissolve in excess of KCN and give soluble potassium cuprocyanide 2CuSO 4 + 4KCN 2CuCN + (CN) 2 + 2K 2 SO 4 CuCN + 3KCN K 3 [Cu(CN) 4 ]
The hypothetical complex chloro diaquatriammine cobalt(III) chloride can be broken down as follows : chloro indicates the presence of a chloride ion (Cl⁻) as a ligand. diaqua indicates the presence of two water molecules (H₂O) as ligands. triammine indicates the presence of three ammonia molecules (NH₃) as ligands. cobalt(III) indicates that cobalt is in the +3 oxidation state.
The additional chloride at the end suggests the presence of chloride ions outside the coordination sphere, likely as counterions.
Given this, let's analyze the options : Option A - [CoCl(NH₃)₃(H₂O)₂]Cl₂ : This matches the description.
It has one chloro ligand, three ammonia ligands, two water ligands, and two chloride ions as counterions, with cobalt in the +3 oxidation state.
Option B - [Co(NH₃)₃(H₂O)Cl₃] : Incorrect, as it suggests three chloride ligands inside the coordination sphere, which is not specified in the name.
Option C - [Co(NH₂)₃(H₂O)₂Cl] : Incorrect, as NH₂ is not the same as NH₃ (ammonia), and it also suggests a different ligand arrangement.
Option D - [Co(NH₃)₃(H₂O)₃]Cl₃ : Incorrect, as it has three water molecules instead of two and lacks the chloro ligand inside the coordination sphere.
Therefore, the correct representation is Option A - [CoCl(NH₃)₃(H₂O)₂]Cl₂ .
Copper being more electropositive readily precipitate silver from their salt (Ag + ) solution.
Cu + 2AgNO 3 Cu(NO 3 ) 2 + Ag In K[Ag(CN) 2 ] solution a complex anion [Ag(CN) 2 ] – is formed so Ag + ions are less available in the solution and Cu cannot displace Ag from this complex ion.
[Co(CO) 5 NH 3 ] 2+ : In this complex, Co-atom is attached with NH 3 through bonding and with CO with dative -bond.
Coordination number of nickel in [Ni(C 2 O 4 ) 3 ] 4 is 6 because C 2 O 4 2– is a bidentate ligand.
Ionic conductance increases with increasing the number of ions, produced after decomposition.
In K 4 [Fe(CN) 6 ], it produces maximum 5 ions thus show more conductivity.
K 4 [Fe(CN) 6 ] ⇌ 4K + + [Fe(CN) 6 ] 4–
In [Cr(SCN) 2 (NH 3 ) 4 ] + it shows linakge, geometrical and optical isomerism.