Coordination Compounds

NEET Chemistry · 85 questions · Page 9 of 9 · Click an option or "Show Solution" to reveal answer

Q81

Which statement is incorrect?

A Ni(CO) 4

-

tetrahedral, paramagnetic

B Ni(CN) 4 - square planar, diamagnetic

C Ni(CO) 4 - tetrahedral, diamagnetic

D [Ni(Cl) 4 ] 2

-

- tetrahedral, paramagnetic.

Correct Answer

Option A

Solution

In Ni(CO) 4 - , Ni in zero oxidation state Ni(0) = [Ar] 3d 8 4s 2 It has no unpaired electron so acts as diamagnetic and has tetrahedral structure.

Q82

In quantitative analysis of second group in laboratory, H 2 S gas is passed in acidic medium for precipitation. When Cu 2+ react with KCN, then for product, true statement is

A K 2 [Cu(CN) 4 ] more soluble

B K 2 [Cd(CN) 4 ] less stable

C K 2 [Cu(CN) 2 ] less stable

D K 2 [Cd(CN) 3 ] more stable

Correct Answer

Option C

Solution

K 3 [Cu(CN) 2 ] = 3(+1)+x+2(-1) = 0 $\Rightarrow$ x = -1 $\therefore$ the oxidation no. of 'Cu' is -1 (-ve), so this complex is unstable so it is not formed.

Q83

Shape of Fe(CO) 5 is

A octahedral

B square planar

C trigonal bipyramidal

D square pyramidal.

Correct Answer

Option C

Solution

In Fe(CO) 5 , the Fe-atom is dsp 3 hybridised and has shape of trigonal bipyramidal. 26 Fe = [Ar]3d 6 4s 2

Q84

Which complex compound will give four isomers?

A [Fe(en) 3 ]Cl 3

B [Co(en) 2 Cl 2 ]Cl

C [Fe(PPh 3 ) 3 NH 3 ClBr]Cl

D [Co(PPh 3 ) 3 Cl]Cl 3

Correct Answer

Option B

Solution

Complex [Co(en) 2 Cl 2 ]Cl show 4 different isomerism.

Q85

Out of the following complex compounds, which of the compound will be having the minimum conductance solution?

\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_3

\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}

\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right]

\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]

Correct Answer

Option C

Solution

Conductance of any complex depends on the following factor.

(1) Number of ions produced by complex.

(2) If number of ions are same then we will check charge on complex unit.

(1) $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_3 \rightarrow\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{+3}+3 \mathrm{Cl}^{-}$ (2) $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl} \rightarrow\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right]^{+}+\mathrm{Cl}^{-}$ $\left.\begin{array}{l}\text{ (3) }\left[\mathrm{Co}^{+3}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right] \\ \text{ (4) }\left[\mathrm{Co}^{+2}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]\end{array}\right\}$ Both complex units have no charge.

Therefore both complex units have same conductance.

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